Question

find the value of x and y if 3^x-1=9and 4^y+2=64​

Answer 1

Answer:

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Answer 2

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$\bf\Huge\blue{\mid{\overline{\underline{ ANSWER }}}\mid }$

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$\Large{\fbox{\color{purple}{QUESTION}}}$

Find the value of x and y:-

1. $3^{(x - 1)}$ = 9

2. $4^{(y + 2)}$ = 64

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$\Large{\fbox{\color{purple}{ANSWER;-}}}$

1. x = 3(Ans)

2. y = 1(Ans)

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$\Large{\fbox{\color{orange}{STEPS;-}}}$

--> $3^{(x - 1)} = 9$

0_0 --> since, 3 × 3 = 9 = $3^{(2)}$ ^_^ 

--> $3^{(x - 1)} = 3^{(2)}$

On comparing;-

=> x - 1 = 2

=> x = 2 + 1

=> x = $\boxed{3}$(Ans)

Similarly,

--> $4^{(y + 2)} = 64$

0_0 --> since, 4 × 4 × 4 = 64 = $4^{(3)}$ ^_^ 

--> $4^{(y + 2)} = 4^{(3)}$

On comparing;-

=> y + 2 = 3

=> y = 3 - 2

=> y = $\boxed{1}$(Ans)

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