Question

Find the value of x and y if x-y=2and 1/x+y=2/3?​

Answer 1

Answer:

6.50

Step-by-step explanation:

x+y = 3.

x+y = 3.x - y = 2.

x+y = 3.x - y = 2.-- (1)

x+y = 3.x - y = 2.-- (1)---

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get2.5+ y = 3

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get2.5+ y = 3y = 3-2.5

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get2.5+ y = 3y = 3-2.5y = 0.5

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get2.5+ y = 3y = 3-2.5y = 0.5x^2 + y^2 = (2.5)^2 + (0.5)^2

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get2.5+ y = 3y = 3-2.5y = 0.5x^2 + y^2 = (2.5)^2 + (0.5)^2= 6.25 +0.25

x+y = 3.x - y = 2.-- (1)---- ( 'II ) ---by adding the equations ( 1 ) & ('ll ) we get2x = 5x = 2.5putting x = 2.5 in equation (1) we get2.5+ y = 3y = 3-2.5y = 0.5x^2 + y^2 = (2.5)^2 + (0.5)^2= 6.25 +0.25= 6.50

Required Answeris 6.50