find the value of x and y in each figures (ii)
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in the triangle ,whose angles were
- 90°
- ×°
- 30°
by taking that triangle ,
sum of all the angles in a triangle = 180°
x°+90°+30° = 180°.
x + 120° = 180°.
x= 180° - 120°
x= 60°
then in the triangle whose angles were
- x°=60°
- 20°
- the angle Adjacent to y° (A°)
sum of the angles in triangle= 180°
A°+20°+60° =180°
A° +80° = 180°
A°= 180°-80°
A°=100°
and
the angles that are adjacent in a straight base side were
- A°=100°
- y°
sum of the adjacent angles= 180°
100°+ y° = 180°
y° = 180° -100°
y° =80°
therefore ,
- x°=60°
- y°=80°
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