Question

Find the value of x and y in the following figure.

Answer 1

since the above figure is a rectangle
the we know that
opp sides of a rectangle are equal
acc to the question
x+3y=13
x=13-3y ......(i)
also
3x+y=7
3(13-3y)+y=7 ( using (i))
39-9y+y=7
-8y=7-39
-8y=-32
y=4
now
x=13-12
x=1
hope this helps you

Answer 2

$\bf\huge{\underline{\underline{Solution}}}$

By property of rectangle,

Lengths are equal i.e., CD = AB

=> x + 3y = 13 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀...(i)

Breadth are equal i.e., AD = BC

=> 3x + y = 7 ⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀...(ii)

On multiplying eq. (ii) by 3 and then subtracting eq. (i), we get

⠀ 8x = 8

=> x = 1

On putting x = 1 in eq.(i), we get

3y = 12 => y = 4

Hence, the required values of x and y are 1 and 4, respectively.