find the value of x and y where root2-1/root2+1=x+yroot2
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Answer:
x=3,y=-2
Step-by-step explanation:
Given,
√2-1/√2+1=x+y√2
By rationalising,We get,
√2-1/√2+1*√2-1/√2-1=x+y√2
(√2-1)²/(√2)²-1²=x+y√2
2+1-2√2/2-1=x+y√2
3-2√2=x+y√2
From the above equation,We can find that
x=3,y=-2
Hope it helps you
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