Question

find the value of x cube + 1 by x cube

Answer 1

Given,

${x}^{2} + \frac{1}{ {x}^{2} } = 98$

$( {x + \frac{1}{x} })^{2} \\ = > {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 98 + 2$

$= > (x + \frac{1}{x}) {}^{2} = 100$

$= >x + \frac{1}{x} = 10$

$(x + \frac{1}{x}) {}^{3} = {10}^{3}$

$= > {x}^{3} + \frac{1}{ {x}^{3} } + 3(x \times \frac{1}{x} )(x + y) = 1000$

${x}^{3} + \frac{1}{ {x}^{3} } + 30 = 1000$

$= > {x}^{3} + \frac{1}{ {x}^{3} } = 1000 - 30 = 970$

Answer 2

Answer:

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