Find the value of x cube+y cube +12xy - 64 when x+y=4
with all steps
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Answered by
3
Given Equation is x + y = 4.
On cubing both sides, we get
= > (x + y)^3 = (4)^3
= > x^3 + y^3 + 3xy(x + y) = 64
= > x^3 + y^3 + 3xy(4) = 64
= > x^3 + y^3 + 12xy = 64
= > x^3 + y^3 + 12xy - 64 = 0.
Hope this helps!
Answered by
1
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THANK YOU ✌
HOPE IT HELPS YOU ☺
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siddhartharao77:
it will be 0
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