Question

Find the value of x cube+y cube +12xy - 64 when x+y=4
with all steps

Answer 1

Given Equation is x + y = 4.

On cubing both sides, we get

= > (x + y)^3 = (4)^3

= > x^3 + y^3 + 3xy(x + y) = 64

= > x^3 + y^3 + 3xy(4) = 64

= > x^3 + y^3 + 12xy = 64

= > x^3 + y^3 + 12xy - 64 = 0.

Hope this helps!

Answer 2

✔✔heya here is ur answer ☺☺

THANK YOU ✌

HOPE IT HELPS YOU ☺