Find the value of x cube +y cube +15xy-125 when x+y=5
Answers
It is given that ,
x + y = 5 ----( 1 )
Do the cube both sides of the
equation ( 1 ) , we get
x³ + y³ + 3xy( x + y ) = 5³
=> x³ + y³ + 3xy × 5 = 125
=> x³ + y³ + 15xy = 125
=> x³ + y³ + 15xy - 125 = 0
••••
Answer:Solution :
It is given that ,
x + y = 5 ----( 1 )
Do the cube both sides of the
equation ( 1 ) , we get
x³ + y³ + 3xy( x + y ) = 5³
=> x³ + y³ + 3xy × 5 = 125
=> x³ + y³ + 15xy = 125
=> x³ + y³ + 15xy - 125 = 0
••••
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