FIND THE VALUE OF x...
FIND THE X
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Step-by-step explanation:
Here, a=1 and d=3.
Let it contain n terms.
As we know, the sum of n terms of an A.P.
Sn=2n×[2a+(n−1)d]
Then,
2n⋅[2a+(n−1)d]=715
⇒2n⋅[2×1+(n−1)×3]=715
⇒n(3n−1)=1430
⇒3n2−n−1430=0
⇒3n2−66n+65n−1430=0
⇒3n(n−22)+65(n−22)=0
⇒(n−22)(3n+65)=0
⇒n=22
∴x=T22=(a+21d)=(1+21×3)=64.
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64
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