Math, asked by manfateh, 1 year ago

find the value of x for (2^-1+4^-1+6^-1+8^-1)^x=1


manfateh: please answer this question

Answers

Answered by faizysuri
6
Q.     (2^-1 + 4^-1 + 6^-1 + 8^-1 )^x = 1
=>     (1/2  +  1/4  +  1/6  +  1/8  )^x  = 1
=>     [ (12+6+4+3)/24 ]^x = 1
=>     (25/24)^x  =  1

which is only possible when X=0 . As any number raised to the power Zero is equal to One .
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