find the value of x for a.p and a.p series is given
1+6+11+16....+x=148
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given,
a=1
last term (l) = x
sum of terms till l = 148
we know that
Sn = (n/2)(2a+(n-1)d)
148 = (n/2)(2+5n-5)
296 = n(5n-3)
5n×n-3n-296=0
on solving this we get,
n= -37/5 or 8
since number of terms can not be negative
n=8
so, x is the 8th term
then,
x= 1 + (8-1)5
x= 3
mark me the brainliest
a=1
last term (l) = x
sum of terms till l = 148
we know that
Sn = (n/2)(2a+(n-1)d)
148 = (n/2)(2+5n-5)
296 = n(5n-3)
5n×n-3n-296=0
on solving this we get,
n= -37/5 or 8
since number of terms can not be negative
n=8
so, x is the 8th term
then,
x= 1 + (8-1)5
x= 3
mark me the brainliest
kunaljj:
so my answer is the brainliest among the two
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