Question

Find the value of x for each of the following:
a)
$x {}^{5} \div x {}^{3} equal \: to \frac{9}{16}$
b)
$( \frac{4}{15} ) {3}^{} \times ( \frac{4}{15} ) { }^{ - 2} equals \: to( \frac{4}{15} ) {2x}^{ + 1}$
please answer.​

Answer 1

Answer:

9

—-

16

=24

Step-by-step explanation:

Answer 2

Answer:-

$a) \: \: \: {x}^{5} \div {x}^{3} = \frac{9}{16}$

$= > \frac{ {x}^{5} }{ {x}^{3} } = \frac{9}{16}$

$= > {x}^{(5 - 3)} = {( \frac{3}{4}) }^{2}$

$= > {x}^{2} = {( \frac{3}{4}) }^{2}$

$= > x = \frac{3}{4}$

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