Math, asked by vindr2077, 3 months ago

Find the value of x for which 2x, (x+10) and (3x +2) are the three consecutive terms

of an AP

Answers

Answered by vaishubh1707

1

Answer:

x= 6

Step-by-step explanation:

If terms are in AP

then a2-a1=a3-a2

x+10 -2x = 3x+2-x-10

-x +10 = 2x-8

10+8= 2x+x

3x = 18

x = 6

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