Math, asked by koliuday81, 3 months ago

find the value of x for which (3/7)^4 × (3/7)^-7 = (3/7)^2x-1​

Answers

Answered by radhikamutturaj
2

Answer:

-1

Step-by-step explanation:

. 3 × 7^7 . = . 3^2x-1 .

7⁴ × 3^7 7^2x-1

(3/7)^-3 = (3/7)^2x-1

2x-1 = -3

2x = -2

x = -1

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