Find the value of x for which 32= 2rais to power x
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Answered by
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Given that
2^x=32
2^x= 2×2×2×2×2
2^x=2^5
Thus by comparing, x=5
2^x=32
2^x= 2×2×2×2×2
2^x=2^5
Thus by comparing, x=5
AnkuriBhabhi:
Bhai kya hai answer
Answered by
1
hey mate:
solution be:
_________
![= > 32 = {2}^{x } \\ = > {2}^{5} = {2}^{x} \: \: \: \: \: \: \: (32 = 2 \times 2 \times 2 \times 2 \times 2) \\ = > comparing \: of \: bases \\ = > 5 = x \: \: (here \: bases \: are \: same) \\ = > x = 5 \\ = > 32 = {2}^{x } \\ = > {2}^{5} = {2}^{x} \: \: \: \: \: \: \: (32 = 2 \times 2 \times 2 \times 2 \times 2) \\ = > comparing \: of \: bases \\ = > 5 = x \: \: (here \: bases \: are \: same) \\ = > x = 5 \\](https://tex.z-dn.net/?f=+%3D++%26gt%3B+32+%3D++%7B2%7D%5E%7Bx+%7D++%5C%5C++%3D++%26gt%3B+++%7B2%7D%5E%7B5%7D++%3D++%7B2%7D%5E%7Bx%7D++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+%2832+%3D+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2%29+%5C%5C++%3D++%26gt%3B+comparing+%5C%3A+of+%5C%3A+bases+%5C%5C++%3D+%26gt%3B++5++%3D+x+%5C%3A++%5C%3A+%28here+%5C%3A+bases+%5C%3A+are+%5C%3A+same%29+%5C%5C++%3D++%26gt%3B+x+%3D+5+%5C%5C+)
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solution be:
_________
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