Question

find the value of x for which (5x+2)
(4x-1) and (x+2) are
are in Ap​

Answer 1

a1 = 5x + 2

a2 = 4x - 1

a3 = x + 2

a2 - a1 = a3 - a2

difference of consecutive numbers in a ap is same.

= $4x - 1 - ( 5x + 2 ) = x + 2 - ( 4x - 1 )$

$= 4x - 1 - 5x - 2 = x + 2 - 4x + 1$

$= -x -3 = -3x + 3$

$-x + 3x = 3 + 3$

$2x = 6$

$x = \frac{6}{2} = 3$

the value of x is 3

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