Find the value of x for which (5x+2),(4x-1) and (x+2) are in AP
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a1 = (5x+2) , a2 = (4x-1) and a3 = ( X+2) are in AP
d = a2 -a1 = = 4x -1 -5x -2 = -x -3
d = a3 - a2 = X+2 - 4x + 1 = -3x +3
Equating the RHS of both the d
-x-3 = -3x+3
=> -x+3x = 3+3
=> 2x = 6
=> X = 6/2
=> X = 3
Answered by
2
Answer:
x=3....................
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