find the value of x for which 8x+4,6x-2 and 2x+7 are in ap
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Hello friend ,I think your question is worng because the number you given are not in ap.
sheerleyrajput123:
Here I know the end.
It's in an ap a2-a3=a2-a1
Answer will be 15/2 cause subtraction done here is wrong
Answered by
2
Here's your answer
a1=8x+4
a2=6x-2
a3=2x+7
In an a.p. a2-a1=a3-a2
6x-2-8x-4=2x+7-6x+2
-2x-8=-4x+9
-2x+4x=9+8
2x=17
x=17/2
a1=8x+4
a2=6x-2
a3=2x+7
In an a.p. a2-a1=a3-a2
6x-2-8x-4=2x+7-6x+2
-2x-8=-4x+9
-2x+4x=9+8
2x=17
x=17/2
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