Find the value of x from the given figure,in which O is the center of the circle
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Answer:
50 degree
Step-by-step explanation:
Angle A =40 degree
then Angle BOC= 40 × 2
Angle BOC= 40 × 2 =80 degree
In triangle OBC,
OB=OC (all radius of a circle are equal )
then triangle OBC is a isosceles triangle,
therefore
Angle OCB= Angle OBC
Let us take Angle OCB and Angle OBC as 'x'
in triangle OBC,
Angle BOC+ Angle OCB+ Angle OBC= 180 degree (Angle sum property)
80 degree + Angle OCB+ Angle OBC= 180 degree
80 degree+ x+ x= 180degree
80 degree+ 2x = 180degree
2x= = 180degree -80 degree
2x=100 degree
x=100/2
therefore, x= 50 degree
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