Find the value of x
(i)x/2-1/4=1/4. (ii)x-5/3=x-3/5
(iii)9x/7-6=15.
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1. x/2=1/4+1/4. x/2=1/2. x=1. 2 x-5/3=x-3/5. 0=2/5.no value of x satisfy this.3. 9x/7=15+6. 9x/7=21. x=7×21/9. x=147/9
arhanabordoloi:
I can't understand
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Hope this helps you.
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What is the value of x in (ii) ?
There is no value of x.
As you can see that both x in RHS and LHS cancel each other, so we cannot take out value of x mathematically.
OK . Thank you
You're welcome.
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