Find the value of X if (3)^2x+3 = (81)^5+x
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Answer:
Given
3
2x
3
5x
×81
2
×6561
=3
7
⟹
3
2x
3
5x
×(3
4
)
2
×3
8
=3
7
⟹
3
2x
3
5x
×3
8
×3
8
=3
7
⟹
3
2x
3
5x+16
=3
7
⟹3
5x+16−2x
=3
7
⟹3
3x+16
=3
7
⟹3x+16=7
⟹3x=−9
⟹x=−3
Step-by-step explanation:
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