Question

find the value of x if (32-x-2)(x+4)=253​

Answer 1

Answer:

(32-x-2)(x+4)=253​

(30-x)(x+4)=253

30x+120-$x^{2}$-4x=253

-$x^{2}$+26x+120=253

-$x^{2}$+26x+120-253=0

-$x^{2}$+26x-133=0

$x^{2}$-26x+133=0                                                 sum= -26,product=133

$x^{2}$-19x-7x+133=0                                               -19,-7

x(x-19)-7(x-19)=0

(x-7)(x-19)=0

x=7 ,x=19

Step-by-step explanation: