Question

Find the value of x, if

(5/7)^5+x × (25/49)^x =(7/5)^2​

Answer 1

$\begin{gathered}( \frac{5}{7} ) {}^{5 + x} \times ( \frac{25}{49}) {}^{x} = (\frac{7}{5})^{2} \\ ( \frac{5}{7} )^{5 + x} \times \sqrt{ (\frac{25}{49}) {}^{x}} =( \frac{7}{5})^{2} \\ \\ ( \frac{5}{7} ) {}^{5 + x + x} = (\frac{7}{5})^{2} \\ \sf \cancel\frac{5}{7} {}^{5 + 2x} = \sf \cancel\frac{7}{5}^{2} \\ 5 + 2x = 2 \\ 2x = 5 - 2 \\ 2x = 3 \\ x = \frac{3}{2} \end{gathered}$

Answer 2

Answer:

Given that x-(5/7)-5'(7/5) 7

so,

first of all let the value (5/7y-5 be as it is

and the value (7/5Y-7 is

(6/77

and now

from the question

(5/7145*(5/7/7= it is in the form of

a man is a mountain

so,

it will be becoming as

(5/71-5+7

it is (5/7/2

it is 25/49

and now the value of x is 25/49

and the value of 2x+1

2x+1 is 2(25/49)+1

is equal to 50/49+1

after by the lem

is equal to the 50+49/49

99/49

it is the answer

hope u this answer will be helpful to u

enjoy ur day my Reshma sister