Question

Find the value of x if 8^3x/2^10 =4^2x/16

Answer 1

Answer → x $=> \frac{6}{5}$

Explanation →

Given that :

$= > \frac{8 {}^{3x} }{2 {}^{10} } = \frac{4 {}^{2x} }{16} \\ \\ </p><p> = > \frac{(2 {}^{3} ) {}^{3x} }{2 {}^{10} } </p><p>= \frac{(2 {}^{2}) {}^{2x} }{(2 {}^{4}) } \\ \\ = > \frac{2 {}^{9x} }{2 {}^{10} } = \frac{2 {}^{4x} }{2 {}^{4} } \\ \\ = > 2 {}^{9x - 10} = 2 {}^{4x - 4}$

➭ 9x - 10 = 4x - 4

➭ 9x - 4x = -4 + 10

➭ 5x = 6

•°• $\boxed x = 6/5$

Things to Remember :

→(aⁿ)^m = a^mn

→When base is same , powers are added

→$\frac{a{}^m}{ a{}^n}$ = a^ (m - n)

$\sf{\underline{Thanks!!}}$

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Answer 2

Step-by-step explanation:

Product of extreme=product of means

4×16=8×x

64=8x

X=64/8

X=8

So this is your answer.

Have a great day!

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