Find the value of x if ; (√9)^2x-1\2=1\81
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(√9)^2x-1/2 = 1/81
3^2x-1/2 = 1/(3)⁴. (as √9 = 3)
3^2x-1/2 = 3^-⁴. (as 1/a^m = a^-m)
as base are equal exponents are equal
so 3 gets cancelled out
2x-1/2 = -4
(4x-1)/2 = -4
4x-1 = -8
x = -7/4
hope this helps
3^2x-1/2 = 1/(3)⁴. (as √9 = 3)
3^2x-1/2 = 3^-⁴. (as 1/a^m = a^-m)
as base are equal exponents are equal
so 3 gets cancelled out
2x-1/2 = -4
(4x-1)/2 = -4
4x-1 = -8
x = -7/4
hope this helps
Catastrophe001:
well thanks ? but can you think more on it as in my book the answer given is -15\4
is it 2x - 1/2 or (2x-1)/2 i mean (2x-1) is numerator RIGHT ?????
no its 2x - 1\2
ohhh thats the problem
I think my book's answer is printed wrong
as my answer is also same
yeah the correct answer is -7/4
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Heya
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well thanks ! but can u think more on it as in my book the answer is -15\4
The answer will be -7/4...I guess there's some printing mistake in your book ^_^
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