Question

find the value of x, if a+1= 0 and x²+ax-6=0.......
please solve .....
quadratic equations​

Answer 1

Answer:

hey isha here is your answer

Step-by-step explanation:

as, a+1 = 0

therefore, a=-1

so now putting the value of a in equation

x²-1x-6=0

here a= 1, b = -1, c= 6

now,

b²-4ac

(-1) ²-4*(-1) (6)

1+24

=25

therefore,

√b²-4ac

=√25

=5

therefore,

x= (-b ± √b²-4ac) /2a

x= {-(-1) ± 5} / 2*1

x= ( 1+5) /2 or (1-5) /2

x= 6/2 or -4/2

x= 3 Or -2

hope it helps you

please follow me

and Mark me as brainliest