find the value of x if angle abo is 25, angle aco is 30
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We have OB=OA(radii of the same circle)
Therefore OAB is an issosceles triangle
Angle OBA =AngleOAB
In Triangle OAB
Angle OAB =20 degree
Similarly in triangle OAC
Angle OAC =30 degree
Total angle BAC =50 degree
We know, BAC =halfBOC
Therefore angle boc =100 degree
Hence founded
sprao534:
angleOAB=20. How?
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25+30=55 (angle substented at the circumference)
x= 55*2=110 ( double at the centre)
x= 55*2=110 ( double at the centre)
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