If p + q = 13 and pq = 22, then find p2 + q2.
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Answered by
109
p+q=13
p q=22
(p+q)^2=p^2+2pq +q^2
169= p^2+q^2+44
169-44=p^2+q^2
125=p^2+q^2
hope it help
plzzz mark as brainliest answer
p q=22
(p+q)^2=p^2+2pq +q^2
169= p^2+q^2+44
169-44=p^2+q^2
125=p^2+q^2
hope it help
plzzz mark as brainliest answer
Answered by
51
pq=22
p+q=13
p^2+2pq+q^2=(p+q)^2. 13^2=169
p^2+q^2+44=169. 22+22=44
p^2+q^2=169-44
p^2+q^2=125
please mark as brainliest
p+q=13
p^2+2pq+q^2=(p+q)^2. 13^2=169
p^2+q^2+44=169. 22+22=44
p^2+q^2=169-44
p^2+q^2=125
please mark as brainliest
Anonymous:
what is ^ this
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