Question

find the value of x if distance between the points is (x-1) and (3,2) is 5

Answer 1

Answer:

given (x, -1) and (3, 2) d = 5

formula used d = √[(x₂ - x₁)²+(y₂-y₁)²]

5 = √(3-x)²+(2-(-1))²

5 = √(9+x²-6x) + 3²

5= √(x²-6x+9+9)

25 = x²-6x+18 [ squaring both sides ]

x²-6x-7 = 0

x² -7x+x-7=0

x(x-7)+1(x-7)=0

(x+1)(x-7) = 0

x+1=0 and x-7 =0

x= -1 and x = 7