Question

find the value of x if number is divisible by 9 - a) 53x21 b) 3x1207. c) 763x312

Answer 1

For Divisibility of 9:-
The Sum Of Digits Of Number Should Be Divisible By 9

A)53x21
5+3+2+1=11
11+x=18(Divisible by 9)
x=7

B)3x1207
3+1+2+0+7=13
13+x=18(Divisible by 9)
x=5

C)763x312
7+6+3+3+1+2
22+x=27(Divisible by 9)
x=5

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Answer 2

A) X= 7       B)X = 5         C)X= 5

Given:

Given numbers are divisible by 9

To find:

The value of x.

explanation:

When sum of all the number is divisible by 9 then number is also divisible by 9.

A)53x21 = 5 + 3 + x+ 2+1 = 11+x

11+x must be divisible by 9

So that 11+x = 18

                x= 7

Similar way

B) 3x1207 ⇒ 3+x+1+2+0+7 = 13 + x

                     13+x = 18 ⇒ x = 5

C)763x312 ⇒ 7+6+3+x+3+1+2 = 22+x

                           22+x = 27

                                 x =5

To learn more...

1)How many three digit number are divisible by 9.

https://brainly.in/question/5487322

2)two digit number is divisible by 9. Number when multiplied by the sum of the digits is 486. Given that the digits are unequal find the number.

https://brainly.in/question/706808