Question

find the value of x if pqx = (3p+q)²-(3p-q)²

Answer 1

Answer:

x = 12

Step-by-step explanation:

$pqx = (3p + q) ^{2} - (3p - q) ^{2}$

$pqx = ((3p) ^{2} + (q) ^{2} + 2(3p)(q)) - ((3p) ^{2} + (q) ^{2} - 2(3p)q )$

$pqx = (3p) ^{2} + q ^{2} + 6pq - (3p) ^{2} - q ^{2} + 6pq$

$pqx = 12pq$

$x = 12pq \div pq$

$x = 12$

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