find the value of x if the distance between a(9,-5) and b(12,x)is three.
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Answered by
1
AB=√(12-9)(12-9)-(x+5)(x+5)
3=√9+x.x+10x+25
on Squaring both sides,
9=9+x.x+10x+25
on solving, X= -5
3=√9+x.x+10x+25
on Squaring both sides,
9=9+x.x+10x+25
on solving, X= -5
Answered by
1
By distance formula,
d=distance.
d=√{(12-9)²+(x-(-5))²}
3=√{3²+(x+5)²}
3²=3²+(x+5)²
0=x²+25+10x
0=x²+10x+25
0=x²+(5+5)x+25
0=x²+5x+5x+25
0=x(x+5)+5(x+5)
0=(x+5)(x+5)
Then x=-5
I hope this much will help you
d=distance.
d=√{(12-9)²+(x-(-5))²}
3=√{3²+(x+5)²}
3²=3²+(x+5)²
0=x²+25+10x
0=x²+10x+25
0=x²+(5+5)x+25
0=x²+5x+5x+25
0=x(x+5)+5(x+5)
0=(x+5)(x+5)
Then x=-5
I hope this much will help you
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