Find the value of x if x,(2x+13°),(3x+10°) and (x-6°) are the angles of a quadrilateral?
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angles of quadrilateral =x,(2x+13),(3x+10),(x-6)
sum of angles of a quadrilateral=360degree
x+(2x+13)+(3x+10)+(x-6)=360
x+2x+13+3x+10+x-6=360
7x+17=360
7x=360-17= 343
7x=343
x =343/7=49
therefore value of x is 49
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