Math, asked by shivani60065, 11 months ago

Find the value of 'X' in
5(X-2) = 5X(-2)-5X²​

Answers

Answered by apm43
0

5x - 10 =  - 10 x - 5 \times   ^{2}  \\ 5x + 10 \times  = 10 - 5x ^{2}  \\ 15x = 10 - 5x ^{2}  \\ x =  \frac{10 - 5x ^{2} }{15 }  \\
Answered by tejasjeet
0

5(x - 2) = 5x( - 2) - 5x^{2}

5x-10=-10x-5x^2

5x+5x^2-10x=10

5x^3-10x=10

 - 5x =  \sqrt[3]{10}

LCM:- 2×5=10

5×2=10

 - 5x =  \sqrt[3]{2 \times 5 }

aage mujhe nhi aata

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