Math, asked by vaidehi74, 1 year ago

find the value of X in each of the following 27/125=(x/5)^3

Answers

Answered by MOSFET01
3
3³/5³=(x³/5³)

x³=(3³/5³)×5³

x³=3³

x=³√3³
.
----×××××××××××××××××××---
x=3

3³.5^-3=x³/5³

3³=x³/5³.5^-3

3³=x³/5^3-3

3³=x³/5^0

3³=x³/1

3 =x

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