find the value of x in each of the following
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SSSolutionSSSolutionSSolutioSSolutionSSSSolution:x=45°
Step-by-step explanation:
we know that sum of angles in a triangle=180°
given∆PQR and Q is 90°
so angleP+angleQ+angleR=180°
x+90°+x=180°
2x+90°=180°
2x=180°-90°
2x=90°
x=45°
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