find the value of x in given figures
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II)
AMB = PMQ = 35 [Vertical opposite angle]
RQM + MQP = 180 [Linear pair]
100 + MQP = 180
MQP = 180 -100
MQP = 80
PMQ + MQP + PQM = 180 [Angle sum property of triangle]
x + 80 + 35 = 180
x + 115 = 180
x = 180 - 115
x = 65
III)
PQX = RQS = 100 [Vertical Opposite Angle]
QSR + RQS + QRS = 180 [Angle sum property of triangle]
QSR + 100 + 50 = 180
QSR + 150 = 180
QSR = 180 - 150
QSR = 30
QSR + TSQ = 180 [Linear Pair]
x = 180 - QSR
x = 180 - 30
x = 50
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