Question

Find the value of x in given series:-

3,2,11,14,27,34,51, x

Answer 1

3,2,11,14,27,34,51, 62

x = 62.

The sequence differs through this expression:

n²+2, n²-2, n²+2, n²-2, and so on...

Now, if we put n = 1 in n²+2, we get:

(1)²+2 = 3, which is the first term.

Similarly, if we put n = 2 in n²-2, we get:

(2)²-2 = 2, which is the second term.

Again if we put n = 3 in n²+2, we get:

(3)²+2 = 11, which is the third term,

Similarly, if we put n = 4 in n²-2, we get:

(4)²-2 = 14, which is the fourth term.

Again if we put n = 5 in n²+2, we get:

(5)²+2 = 27, which is the fifth term,

Similarly, if we put n = 6 in n²-2, we get:

(6)²-2 = 34, which is the sixth term.

Again if we put n = 7 in n²+2, we get:

(7)²+2 = 51, which is the seventh term,

Similarly, if we put n = 8 in n²-2, we get:

(8)²-2 = 62, which is the eighth and the required term.

So, x = 62.

Answer 2

The value of "x is equal to 62".

Step-by-step explanation:

The given sequence are:

3, 2, 11, 14, 27, 34, 51, x

To find, the value of x = ?

The pattern follow,

$1^{2} +2,2^{2} -2,3^{2} +2,4^{2} -2,5^{2} +2,6^{2} -2,.....$

$3=1^{2} +2=1+2=3$

$2=2^{2} -2=4-2=2$

$11=3^{2} +2=9+2=11$

$14=4^{2} -2=16-2=14$

$27=5^{2} +2=25+2=27$

$34=6^{2} -2=36-2=34$

$51=7^{2} +2=49+2=51$

Similarly,

$x=8^{2} -2=64-2=62$

Hence, the value of "x is equal to 62".