Question

find the value of x in
${ \boxed{ {8}^{2} + {8}^{3} + {8}^{x} = {8}^{12} }}$
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Answer 1

$\Large\bf\red{\underline{\overline{\mid{\orange{Answer:-}}\mid}}}$

${ \boxed{ {8}^{2} + {8}^{3} + {8}^{x} = {8}^{12} }}$

8 ² + 8 ³ + 8 ^ x = 8 ¹²

8 ^ 2 + 3 + x = 8 ¹²

8 ^ 5 + x = 8 ¹²

8 ^ 12 - 5 = 7

${ \boxed{ {8}^{7} }}$

Answer 2

$\huge \sf {\orange {\underline {\red{\underline {❥︎A᭄ɴsᴡᴇʀ࿐ :−}}}}}$

${ {8}^{2} + {8}^{3} + {8}^{x} = {8}^{12} } \\ 8(2+3+x) = {8}^{12} \\ 8(5 + x) = {8}^{12} \\ x = 12 - 5 \\ x = 7 \\ \therefore{8}^{2} + {8}^{3} + {8}^{7} = {8}^{12}$

$\over \underline\colorbox{pink}{Hope This Helps You Anshu Bhaiya Ji..xD}$

Yeh Kon he ab..(O_O)