Math, asked by rishurauniyar03, 3 months ago

please solve it....​

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Answered by beherakhitish12feb20
0

Step-by-step explanation:

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Answered by Sirat4
0

Answer:

√ 1 + (1 /√1 + cot² θ)²

now, 1 + cot² θ = cosec² θ

√1 + (1/√cosec² θ)²                            (square root of cosec² θ)

√1 +  (1/ cosec θ)²                             ( square of 1/ cosec θ)

√ 1 + 1/ cosec² θ               (take LCM cosec² θ)

(cosec²θ + 1)/cosec²  θ        

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