Question

Find the value of x in the figure.(please fast important).​

Answer 1

Answer:

120°

Step-by-step explanation:

Produce R to meet QP at S

now in ∆ QRS,

60°+40°+ ^S = 180° ( ASP)

^S = 180° - 100°

^S = 80°

now in the small traingle,

^S = 180° - 80°

^S = 100° ( LPA)

finally, in the small triangle

^S + 20° = x° ( ext angle)

x° = 100° + 20°

x° = 120°