Find the value of x in the following (14)' = 196
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14X=196
The trick is dividing both sides and to eliminate the denominator.
14x/14=196/14
Coffecient 14 gets canceled at the left and remaining is 14/196 at the right and that is equal to 14
And atlast the remaining variable X becomes:
X=14
Easy right?
For more information regarding algerba and more complicated equations you can always go for pre algerba courses.
That would help you regarding how things are happening and how it does makes a sense.
Thank you
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