Question

find the value of x in the following equations. (4)^-2x=(1/32)^3x-4​

Answer 1

Answer:

$({4})^{ - 2x} = ( { \frac{1}{32} })^{3x - 4} \\ \\ = ( {2})^{ - 4x} = ({2})^{ - 5 + 3x - 4} \\ \\ = {2}^{ - 4x} = {2}^{3x - 9} \\ \\ = > - 4x = 3x - 9 \\ \\ = > 3x + 4x = 9 \\ \\ = > 7x = 9 \\ \\ = > x = \frac{9}{7}$