find the value of x in the following figure
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Answer:
x = 130 degrees
Step-by-step explanation:
explanation in the attachment.
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first naming the triangle ABC
ACD = 120°
ACD + ACB = 180° (angles in linear pair)
120° + ACB = 180°
ACB = 180° - 120°
ACB = 60°
similarly
FAB = 110°
FAB + BAD = 180° (angles in linear pair)
110° + BAD = 180°
BAD = 180° - 110°
BAD = 70°
In triangle ABC
ACB + BAD + DBA = 180° (sum of all angles in triangle)
PUT THE VALUES....
60° + 70° + DBA = 180°
130° + DBA = 180°
DBA = 180° - 130°
DBA = 50°
now see
DBE + DBA = 180° (angles in linear pair)
DBE + 50° = 180°
DBE = 180° - 50° = 130°
hence value of angle DBE is 130°
x = 130°
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