Question

help me to solve this​

Answer 1

Answer:

angle PRQ = 30 degree

angle BRQ = 150 degree

angle CPQ = 90 degree

angle RPQ = 90 degree

Answer 2

Answer:

∠PRQ = 30°

∠BRQ = 150°

∠CPQ = 90°

∠RPQ = 90°

Explanation:

We can find ∠PQR by subtracting 90° from 120° since both of them are suplementary, which means we can find the value of the angle by subtracting the other from 180°

∠PQR = 180° - 120°     (Supplementary Angles)

           = 60°

Now, lets find ∠PRQ.

We know some of the angles is 180°, so

∠RPQ + ∠PQR + ∠PRQ = 180°

90° +  60° + ∠PRQ = 180°

150° + ∠PRQ = 180°

∠PRQ = 180° - 150°

∠PRQ = 30°

Now we can find ∠BRQ by using the same suplementary method since both ∠PRQ and ∠BRQ are supplementary...

∠BRQ = 180° - ∠PRQ

∠BRQ = 180° - 30°

∠BRQ = 150°

Now we will find ∠CPQ,

∠CPQ is 90° since the PA is the perpendicular bisector of the line RC. which basically means that since it is shown in the figure that ∠RPQ is 90°, the angle which is right next to it is also 90°, so

∠CPQ = 90°

Now for ∠RPQ,

∠RPQ is 90° since its shown in the figure, if you look carefully at the ∠RPQ, then you can see that there is kind of like a part of a square, that symbol basically means that the angle is 90°, so...

∠RPQ = 90°

Therefore,

∠PRQ = 30°

∠BRQ = 150°

∠CPQ = 90°

∠RPQ = 90°