Question

Find the value of x in the following linear equation:

Answer 1

Answer:

value of x 44

it is correct answer

Answer 2

Answer:

x = 3

Step-by-step explanation:

$\frac{x + 3}{3x + 9} = \frac{4 - x}{x + 3}$

cross multiplying both sides

$(x + 3)(x + 3) = (3x + 9)(4 - x)$

${x}^{2} + 3x + 3x + {3}^{2} = 12x - 9x - 3 {x}^{2} + 36$

${x}^{2} + 6x + 9 = 3x - 3 {x}^{2} + 36$

$3 {x}^{2} + {x}^{2} + 6x - 3x - 36 + 9 = 0$

$4 {x}^{2} + 3x - 27 = 0$

$4 {x}^{2} - 12x + 9x - 27 = 0$

$4x(x - 3) + 9(x - 3) = 0$

$(x - 3)(4x + 9) = 0$

• x = 3
• x = -9/4

value of x can't be in fraction and negetive

Hence ,

x = 3 is the answer.