Math, asked by shahidibrahim19999, 10 months ago

Find the value of x in the given AP ; -3, x, 33, 51, ...

Answers

Answered by gogoiadrash5698
1

x = 15

-3,x,33,51

a= -3

d=51-33=18

n=2

t2= x

t2=a+(n-1)d

x= -3+(2-1)18

x= -3+18 = 15

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