find the value of x in the given figure.
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Step-by-step explanation:
First of all u must know that
IN ANY TRIANGLE EXTERIOR ANGLE IS EQUAL TO THE SUM OF ITS INTERIOR OPPOSITE ANGLE.
So,
/ PQS = /QPR + /QRP
→110= x + 180 – 2x ( linear pairs /PRQ and
/PRT)
→x= 70
Hence your final value of x is 70.
Now one request
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