Find the value of x in the given figure. pls answer fast I'm in great need...
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Answered by
1
Hi friend
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Your answer
-------------------
HERE,
---------
IN ∆AOB, WE HAVE,
------------------------------
OA = OB [ RADIUS OF THE SAME CIRCLE]
THEN, ANGLE OBA= ANGLE OAB = 20°
SO,
ANGLE AOB = 180° - (20+20)° = 180° - 40°= 140°
SIMILARLY
----------------
IN ∆AOC, WE HAVE,
------------------------------
AO = OC [ RADIUS OF THE SAME CIRCLE]
THEN, ANGLE OCA = ANGLE OAC = 30°
SO,
ANGLE AOC = 180°- (30+30)° = 180°- 60° = 120°
NOW,
-------
EXTERIOR ANGLE BOC = X = 360° - (ANGLE AOB+ ANGLE AOC)
= 360° - (140°+ 120°)
= 360° - 260°
= 100°
THEREFORE, X = 100°
HOPE IT HELPS
#ARCHITECTSETHROLLINS
-------------
Your answer
-------------------
HERE,
---------
IN ∆AOB, WE HAVE,
------------------------------
OA = OB [ RADIUS OF THE SAME CIRCLE]
THEN, ANGLE OBA= ANGLE OAB = 20°
SO,
ANGLE AOB = 180° - (20+20)° = 180° - 40°= 140°
SIMILARLY
----------------
IN ∆AOC, WE HAVE,
------------------------------
AO = OC [ RADIUS OF THE SAME CIRCLE]
THEN, ANGLE OCA = ANGLE OAC = 30°
SO,
ANGLE AOC = 180°- (30+30)° = 180°- 60° = 120°
NOW,
-------
EXTERIOR ANGLE BOC = X = 360° - (ANGLE AOB+ ANGLE AOC)
= 360° - (140°+ 120°)
= 360° - 260°
= 100°
THEREFORE, X = 100°
HOPE IT HELPS
#ARCHITECTSETHROLLINS
ArchitectSethRollins:
please mark my answer as brainliest
Answered by
0
Answer:
x = 100
hope u like it
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