Math, asked by kalpanakushwah369, 1 month ago

find the value of x in the given figure. ∆S=4x-5 ∆R=22-5x


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Answers

Answered by StudyLover000
1

Answer:

In parallelogram PQRS,

∠Q = (4x – 5)° and ∠S = (3x + 10)°

opposite ∠s of //gm are equal.

∠Q = ∠S

4x – 5 = 3x + 10

4x – 3x = 10 + 5

x = 15

∠Q = 4x – 5 =4 x 15 – 5 = 55°

Also ∠Q + ∠R = 180°

55° + ∠R = 180°

∠R = 180°- 55° = 125°

∠Q = 55° ; ∠R = 125°

Step-by-step explanation:

If DE∣∣AB, then ΔCDE∼ΔABC

By property of similar triangles:

AC

CD

=

BC

CE

4x+22

x+3

=

4x+4

x

Cross-multiplying:

(x+3)(4x+4)=x(4x+22)

⟹4x

2

+16x+12=4x

2

+22x

12=6x⟹

x=2

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