find the value of x in the given figure. ∆S=4x-5 ∆R=22-5x
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Answer:
In parallelogram PQRS,
∠Q = (4x – 5)° and ∠S = (3x + 10)°
opposite ∠s of //gm are equal.
∠Q = ∠S
4x – 5 = 3x + 10
4x – 3x = 10 + 5
x = 15
∠Q = 4x – 5 =4 x 15 – 5 = 55°
Also ∠Q + ∠R = 180°
55° + ∠R = 180°
∠R = 180°- 55° = 125°
∠Q = 55° ; ∠R = 125°
Step-by-step explanation:
If DE∣∣AB, then ΔCDE∼ΔABC
By property of similar triangles:
AC
CD
=
BC
CE
⟹
4x+22
x+3
=
4x+4
x
Cross-multiplying:
(x+3)(4x+4)=x(4x+22)
⟹4x
2
+16x+12=4x
2
+22x
12=6x⟹
x=2
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